Optimal. Leaf size=200 \[ \frac{3}{2} i b d e^2 \text{PolyLog}(2,-i c x)-\frac{3}{2} i b d e^2 \text{PolyLog}(2,i c x)-\frac{3 d^2 e \left (a+b \tan ^{-1}(c x)\right )}{2 x^2}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )}{4 x^4}+\frac{1}{2} e^3 x^2 \left (a+b \tan ^{-1}(c x)\right )+3 a d e^2 \log (x)-\frac{3}{2} b c^2 d^2 e \tan ^{-1}(c x)+\frac{b c^3 d^3}{4 x}+\frac{1}{4} b c^4 d^3 \tan ^{-1}(c x)+\frac{b e^3 \tan ^{-1}(c x)}{2 c^2}-\frac{3 b c d^2 e}{2 x}-\frac{b c d^3}{12 x^3}-\frac{b e^3 x}{2 c} \]
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Rubi [A] time = 0.20703, antiderivative size = 200, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {4980, 4852, 325, 203, 4848, 2391, 321} \[ \frac{3}{2} i b d e^2 \text{PolyLog}(2,-i c x)-\frac{3}{2} i b d e^2 \text{PolyLog}(2,i c x)-\frac{3 d^2 e \left (a+b \tan ^{-1}(c x)\right )}{2 x^2}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )}{4 x^4}+\frac{1}{2} e^3 x^2 \left (a+b \tan ^{-1}(c x)\right )+3 a d e^2 \log (x)-\frac{3}{2} b c^2 d^2 e \tan ^{-1}(c x)+\frac{b c^3 d^3}{4 x}+\frac{1}{4} b c^4 d^3 \tan ^{-1}(c x)+\frac{b e^3 \tan ^{-1}(c x)}{2 c^2}-\frac{3 b c d^2 e}{2 x}-\frac{b c d^3}{12 x^3}-\frac{b e^3 x}{2 c} \]
Antiderivative was successfully verified.
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Rule 4980
Rule 4852
Rule 325
Rule 203
Rule 4848
Rule 2391
Rule 321
Rubi steps
\begin{align*} \int \frac{\left (d+e x^2\right )^3 \left (a+b \tan ^{-1}(c x)\right )}{x^5} \, dx &=\int \left (\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )}{x^5}+\frac{3 d^2 e \left (a+b \tan ^{-1}(c x)\right )}{x^3}+\frac{3 d e^2 \left (a+b \tan ^{-1}(c x)\right )}{x}+e^3 x \left (a+b \tan ^{-1}(c x)\right )\right ) \, dx\\ &=d^3 \int \frac{a+b \tan ^{-1}(c x)}{x^5} \, dx+\left (3 d^2 e\right ) \int \frac{a+b \tan ^{-1}(c x)}{x^3} \, dx+\left (3 d e^2\right ) \int \frac{a+b \tan ^{-1}(c x)}{x} \, dx+e^3 \int x \left (a+b \tan ^{-1}(c x)\right ) \, dx\\ &=-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )}{4 x^4}-\frac{3 d^2 e \left (a+b \tan ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^3 x^2 \left (a+b \tan ^{-1}(c x)\right )+3 a d e^2 \log (x)+\frac{1}{4} \left (b c d^3\right ) \int \frac{1}{x^4 \left (1+c^2 x^2\right )} \, dx+\frac{1}{2} \left (3 b c d^2 e\right ) \int \frac{1}{x^2 \left (1+c^2 x^2\right )} \, dx+\frac{1}{2} \left (3 i b d e^2\right ) \int \frac{\log (1-i c x)}{x} \, dx-\frac{1}{2} \left (3 i b d e^2\right ) \int \frac{\log (1+i c x)}{x} \, dx-\frac{1}{2} \left (b c e^3\right ) \int \frac{x^2}{1+c^2 x^2} \, dx\\ &=-\frac{b c d^3}{12 x^3}-\frac{3 b c d^2 e}{2 x}-\frac{b e^3 x}{2 c}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )}{4 x^4}-\frac{3 d^2 e \left (a+b \tan ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^3 x^2 \left (a+b \tan ^{-1}(c x)\right )+3 a d e^2 \log (x)+\frac{3}{2} i b d e^2 \text{Li}_2(-i c x)-\frac{3}{2} i b d e^2 \text{Li}_2(i c x)-\frac{1}{4} \left (b c^3 d^3\right ) \int \frac{1}{x^2 \left (1+c^2 x^2\right )} \, dx-\frac{1}{2} \left (3 b c^3 d^2 e\right ) \int \frac{1}{1+c^2 x^2} \, dx+\frac{\left (b e^3\right ) \int \frac{1}{1+c^2 x^2} \, dx}{2 c}\\ &=-\frac{b c d^3}{12 x^3}+\frac{b c^3 d^3}{4 x}-\frac{3 b c d^2 e}{2 x}-\frac{b e^3 x}{2 c}-\frac{3}{2} b c^2 d^2 e \tan ^{-1}(c x)+\frac{b e^3 \tan ^{-1}(c x)}{2 c^2}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )}{4 x^4}-\frac{3 d^2 e \left (a+b \tan ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^3 x^2 \left (a+b \tan ^{-1}(c x)\right )+3 a d e^2 \log (x)+\frac{3}{2} i b d e^2 \text{Li}_2(-i c x)-\frac{3}{2} i b d e^2 \text{Li}_2(i c x)+\frac{1}{4} \left (b c^5 d^3\right ) \int \frac{1}{1+c^2 x^2} \, dx\\ &=-\frac{b c d^3}{12 x^3}+\frac{b c^3 d^3}{4 x}-\frac{3 b c d^2 e}{2 x}-\frac{b e^3 x}{2 c}+\frac{1}{4} b c^4 d^3 \tan ^{-1}(c x)-\frac{3}{2} b c^2 d^2 e \tan ^{-1}(c x)+\frac{b e^3 \tan ^{-1}(c x)}{2 c^2}-\frac{d^3 \left (a+b \tan ^{-1}(c x)\right )}{4 x^4}-\frac{3 d^2 e \left (a+b \tan ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^3 x^2 \left (a+b \tan ^{-1}(c x)\right )+3 a d e^2 \log (x)+\frac{3}{2} i b d e^2 \text{Li}_2(-i c x)-\frac{3}{2} i b d e^2 \text{Li}_2(i c x)\\ \end{align*}
Mathematica [C] time = 0.206362, size = 169, normalized size = 0.84 \[ \frac{1}{12} \left (-\frac{18 b c d^2 e \text{Hypergeometric2F1}\left (-\frac{1}{2},1,\frac{1}{2},-c^2 x^2\right )}{x}-\frac{b c d^3 \text{Hypergeometric2F1}\left (-\frac{3}{2},1,-\frac{1}{2},-c^2 x^2\right )}{x^3}+18 i b d e^2 \text{PolyLog}(2,-i c x)-18 i b d e^2 \text{PolyLog}(2,i c x)-\frac{18 d^2 e \left (a+b \tan ^{-1}(c x)\right )}{x^2}-\frac{3 d^3 \left (a+b \tan ^{-1}(c x)\right )}{x^4}+6 e^3 x^2 \left (a+b \tan ^{-1}(c x)\right )+36 a d e^2 \log (x)-\frac{6 b e^3 \left (c x-\tan ^{-1}(c x)\right )}{c^2}\right ) \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.056, size = 251, normalized size = 1.3 \begin{align*}{\frac{a{e}^{3}{x}^{2}}{2}}-{\frac{3\,a{d}^{2}e}{2\,{x}^{2}}}-{\frac{a{d}^{3}}{4\,{x}^{4}}}+3\,ad{e}^{2}\ln \left ( cx \right ) +{\frac{b\arctan \left ( cx \right ){e}^{3}{x}^{2}}{2}}-{\frac{3\,b{d}^{2}\arctan \left ( cx \right ) e}{2\,{x}^{2}}}-{\frac{b{d}^{3}\arctan \left ( cx \right ) }{4\,{x}^{4}}}+3\,b\arctan \left ( cx \right ) d{e}^{2}\ln \left ( cx \right ) -{\frac{b{e}^{3}x}{2\,c}}+{\frac{b{c}^{4}{d}^{3}\arctan \left ( cx \right ) }{4}}-{\frac{3\,b{c}^{2}{d}^{2}e\arctan \left ( cx \right ) }{2}}+{\frac{b\arctan \left ( cx \right ){e}^{3}}{2\,{c}^{2}}}+{\frac{b{c}^{3}{d}^{3}}{4\,x}}-{\frac{3\,bc{d}^{2}e}{2\,x}}-{\frac{bc{d}^{3}}{12\,{x}^{3}}}+{\frac{3\,i}{2}}bd{e}^{2}{\it dilog} \left ( 1+icx \right ) -{\frac{3\,i}{2}}bd{e}^{2}{\it dilog} \left ( 1-icx \right ) +{\frac{3\,i}{2}}bd{e}^{2}\ln \left ( cx \right ) \ln \left ( 1+icx \right ) -{\frac{3\,i}{2}}bd{e}^{2}\ln \left ( cx \right ) \ln \left ( 1-icx \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 2.16394, size = 316, normalized size = 1.58 \begin{align*} \frac{1}{2} \, a e^{3} x^{2} + \frac{1}{12} \,{\left ({\left (3 \, c^{3} \arctan \left (c x\right ) + \frac{3 \, c^{2} x^{2} - 1}{x^{3}}\right )} c - \frac{3 \, \arctan \left (c x\right )}{x^{4}}\right )} b d^{3} - \frac{3}{2} \,{\left ({\left (c \arctan \left (c x\right ) + \frac{1}{x}\right )} c + \frac{\arctan \left (c x\right )}{x^{2}}\right )} b d^{2} e + 3 \, a d e^{2} \log \left (x\right ) - \frac{3 \, a d^{2} e}{2 \, x^{2}} - \frac{a d^{3}}{4 \, x^{4}} - \frac{3 \, \pi b c^{2} d e^{2} \log \left (c^{2} x^{2} + 1\right ) - 12 \, b c^{2} d e^{2} \arctan \left (c x\right ) \log \left (x{\left | c \right |}\right ) + 6 i \, b c^{2} d e^{2}{\rm Li}_2\left (i \, c x + 1\right ) - 6 i \, b c^{2} d e^{2}{\rm Li}_2\left (-i \, c x + 1\right ) + 2 \, b c e^{3} x -{\left (2 \, b c^{2} e^{3} x^{2} + 12 i \, b c^{2} d e^{2} \arctan \left (0, c\right ) + 2 \, b e^{3}\right )} \arctan \left (c x\right )}{4 \, c^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{a e^{3} x^{6} + 3 \, a d e^{2} x^{4} + 3 \, a d^{2} e x^{2} + a d^{3} +{\left (b e^{3} x^{6} + 3 \, b d e^{2} x^{4} + 3 \, b d^{2} e x^{2} + b d^{3}\right )} \arctan \left (c x\right )}{x^{5}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b \operatorname{atan}{\left (c x \right )}\right ) \left (d + e x^{2}\right )^{3}}{x^{5}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x^{2} + d\right )}^{3}{\left (b \arctan \left (c x\right ) + a\right )}}{x^{5}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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